2.7x^2+1.9x-3.3=0

Solution for 2.7x^2+1.9x-3.3=0 equation:

2.7x^2+1.9x-3.3=0

a = 2.7; b = 1.9; c = -3.3;
Δ = b2-4ac
Δ = 1.92-4·2.7·(-3.3)
Δ = 39.25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1.9)-\sqrt{39.25}}{2*2.7}=\frac{-1.9-\sqrt{39.25}}{5.4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1.9)+\sqrt{39.25}}{2*2.7}=\frac{-1.9+\sqrt{39.25}}{5.4}
$